Help for this exam paper Q

[Face]

1.JPG (39.78 KiB) Viewed 4646 times

I cant get understand what is the error of this.I found the answer, But can't understand the error.

[Herath]

value is defined a short type variable. But 2 is "int" by default. The error (warning) is loss of precision. Because "int" is 32bit of size. The result of (value*2) is going to be int as I think. Then has to be converted to short in order to be assigned to the "value". So the value has to be cast manually.
possible fixes for this are

Code: Select all

value=(short) ((short) value * (short) 2);

Code: Select all

value*=2;

But you can always cast a 16bit data type in to a 32bit or higher size type without any problem.

[Face]

thanks brother.!