Tutorial on Static Equilibrium
Posted: Wed Nov 11, 2009 12:34 am
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Re: Tutorial on Static Equilibrium
Posted: Fri Sep 23, 2011 6:52 pm
Hello friends,
Thanks to sharing yours static equilibrium information, I highly appreciated!! visit your site learning few tips.
Nice to meet you
Andy Charles
<link removed>
Thanks to sharing yours static equilibrium information, I highly appreciated!! visit your site learning few tips.
Nice to meet you
Andy Charles
<link removed>
Re: Tutorial on Static Equilibrium
Posted: Fri Sep 30, 2011 5:38 pm
Hello everyone,
Thank you for your sharing information, I think I found the right answer, but I am not really sure why it is right.
net torque = (75)(9.8)3sin30 + (10)(9.8)2.5sin30 - 4.33F3 = 0
1102.5 + 122.5 - 4.33F3 = 0
F3 = 282.9 N
The part I don't understand is (4.33)(F3). why does r = 4.33? That would mean that r just goes straight down and the force must be Horizontal. the other two r's are horizontal, and the force goes straight down.
Thanks and regards
Andy Charles
Thank you for your sharing information, I think I found the right answer, but I am not really sure why it is right.
net torque = (75)(9.8)3sin30 + (10)(9.8)2.5sin30 - 4.33F3 = 0
1102.5 + 122.5 - 4.33F3 = 0
F3 = 282.9 N
The part I don't understand is (4.33)(F3). why does r = 4.33? That would mean that r just goes straight down and the force must be Horizontal. the other two r's are horizontal, and the force goes straight down.
Thanks and regards
Andy Charles