Create Pin array in HI TECH C

[Nandika]

Hello Friends,
I want to create pin array in HI TECH C for PIC16F like Arduino.

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int ledPins[] = {2, 7, 4, 6, 5, 3 };

Assume I have PORTB.RB0,RB1....RB7 are my pins now.
I coded like this,

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#define D0 RB0
#define D1 RB1
#define D2 RB2
#define D3 RB3
#define D4 RB4
#define D5 RB5
#define D6 RB6
#define D7 RB7

bit pins_b[]={D0,D1,D2,D3,D4,D5,D6,D7};

Not Worked...
compiler gives following errors...

error.PNG (37.66 KiB) Viewed 5174 times

bit data type not allowed for array implementation.
How can I implement an array with PORTB pins?



Thank in advance

[Neo]

Nandika, after long time. Welcome back.

As per the error says, RB0.... RB8 are not defined. Make sure that you have includes pic.h

Also, I'm wondering why you need such as array to assign to the port. As far as I see it, your purpose is to avoid nested ifs and use the port as a lookup table.

PORTB itself can be used for this purpose using boolean operations (bitwise). So rather than addressing it as pins_b[x], you would address the port as below.

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void writePin(index, value){

     PORTB = (PORTB & ~(1 << index)) | (value << index);
}

Reading the pin can be written as follows,

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int readPin(index){

     return ((PORTB >> index) & 1);
}

You can also use them as preprocessor defines as follows,

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#define WRITE_PIN(index, value)     PORTB = (PORTB & ~(1 << index)) | (value << index)
#deifne READ_PIN(index)      ((PORTB >> index) & 1)

[SemiconductorCat]

>> Also, I'm wondering why you need such as array to assign to the port. As far as I see it, your purpose is to avoid nested ifs and use the port as a lookup table.

I think he need to use that array in a for loop. If so use that index method provided by neo.
as said , you could not create arrays of bits.

And your defines are wrong.
from the sdcc project includes in \device\non-free\include\pic14\pic16f84a.h include header file,
it defines like this.

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#define RA0                  PORTAbits.RA0                  /* bit 0 */
#define RA1                  PORTAbits.RA1                  /* bit 1 */
#define RA2                  PORTAbits.RA2                  /* bit 2 */
#define RA3                  PORTAbits.RA3                  /* bit 3 */
#define RA4                  PORTAbits.RA4                  /* bit 4 */

#define RB0                  PORTBbits.RB0                  /* bit 0 */
#define RB1                  PORTBbits.RB1                  /* bit 1 */
#define RB2                  PORTBbits.RB2                  /* bit 2 */
#define RB3                  PORTBbits.RB3                  /* bit 3 */
#define RB4                  PORTBbits.RB4                  /* bit 4 */
#define RB5                  PORTBbits.RB5                  /* bit 5 */
#define RB6                  PORTBbits.RB6                  /* bit 6 */
#define RB7                  PORTBbits.RB7                  /* bit 7 */

Don't worry to read the header files and if you don't understand what's it, then refer back to the manual of the
compiler and see what's that?
http://www.mikroe.com/download/eng/docu ... l_bits.htm

Every source code file was written by a man for another man first and compiler to the second.


In the case you don't understand what the bellow code ":" , it simply used to limit the number of bits used in
that datatype. So when you need a variable with 3-bits , you could define it inside a structure. Note that
this feature is only avaliable to be used inside 'structures' and classes.

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// ----- PORTB bits --------------------
typedef union {
  struct {
    unsigned char RB0:1;
    unsigned char RB1:1;
    unsigned char RB2:1;
    unsigned char RB3:1;
    unsigned char RB4:1;
    unsigned char RB5:1;
    unsigned char RB6:1;
    unsigned char RB7:1;
  };
} __PORTBbits_t;
extern volatile __PORTBbits_t __at(PORTB_ADDR) PORTBbits;

I think whole the code is clear to you now. Crystal clear? Then nice code reviewing.

[Nandika]

PORTB = (PORTB & ~(1 << index)) | (value << index);
return ((PORTB >> index) & 1);

Nice cording Neo... I got some time to understand it.
Thanks..

SemiconductorCat,
Your coding is hard.I cant understand. because,I couldn't study about some part of your code..Soon I will understand it.